The problem is to draw the line x-2y=3 and find the corresponding y-coordinate for x=-5.
Here are the steps to solve this problem:
1. Rearrange the given equation into slope-intercept form (y=mx+b), which is a format that describes a line with slope m and y-intercept b.
To transform x-2y=3 into this form, first we can subtract x from both sides:
-2y = -x + 3
Then we can divide every term by -2:
y = x/2 - 3/2
Here we have a line with a slope of 1/2 (which means it increases one unit up for every two units to the right), and it crosses the y axis at -3/2.
2. To determine the y-coordinate when x=-5, we can substitute x=-5 into the equation:
y = -5/2 - 3/2
y = -4.
So, when x = -5, y = -4. The coordinates of the point at x=-5 are (-5, -4).
3. Now, we can draw the line, marking the y-intercept at -3/2, drawing a rising slope that increases by 1 unit for every 2 units to the right, and marking the point (-5, -4) which we calculated.
And that's it! You've graphed the line x−2y=3 and found the coordinates of the point when x=−5.