Answer:To determine the resultant force and direction on the 10kg mass, we need to consider the forces acting on the mass and their vector components.
Given:
- Mass = 10kg
- Force pulling the mass = 20N
- Angle of the force above the horizontal = 37°
- Frictional force = 3N
1. Resolve the pulling force into horizontal and vertical components:
- The horizontal component (Fx) can be calculated using the cosine of the angle:
Fx = 20N * cos(37°)
- The vertical component (Fy) can be calculated using the sine of the angle:
Fy = 20N * sin(37°)
2. Determine the net horizontal force:
- The frictional force acts in the opposite direction of the horizontal force, so we subtract it:
Net horizontal force (Fnetx) = Fx - Frictional force
3. Determine the net vertical force:
- The weight of the mass acts downward, so it contributes to the net vertical force:
Weight = mass * acceleration due to gravity = 10kg * 9.8m/s^2
- The vertical component of the pulling force also contributes to the net vertical force:
Net vertical force (Fnety) = Fy - Weight
4. Calculate the resultant force:
- The resultant force (Fnet) can be found using the Pythagorean theorem:
Fnet = sqrt(Fnetx^2 + Fnety^2)
5. Determine the direction of the resultant force:
- The direction of the resultant force can be found using the inverse tangent (arctan) function:
Direction = arctan(Fnety / Fnetx)
By calculating the above steps, we can find the values of the net horizontal force, net vertical force, resultant force, and direction on the 10kg mass.
Please note that the actual numerical calculations are not provided in the question, so you will need to perform the calculations using the given values to determine the final answer.