Question

Homework practice what is the 5th term of this sequence?

Answer 1

`\begin{gathered} a_n=7a_(n-1) \\ a_1=7 \\ a_2=7a_(2-1)=7a_1=7\cdot7=49 \\ a_3=7a_(3-1)=7a_2=7\cdot49=343 \\ a_4=7a_(4-1)=7a_3=7\cdot343=2401 \\ a_5=7a_(5-1)=7a_4=7\cdot2401=16807 \end{gathered}`