Question

A rowing team rode 50 miles while going with the current in the same amount of time as it took to row 25 miles going against the current. The rate of the current was 2 mph. find the rate of the rowing team in Still water

Answer 1

6 mph

Explanation:

To find the rate of the rowing team in still water, we need to consider the relationship between the rowing speed and the current speed.

Let's assume the rate of the rowing team in still water is "r" mph.

When the rowing team is going with the current, the effective speed is increased by the speed of the current. So, the rowing speed becomes "r + 2" mph. They traveled a distance of 50 miles at this speed.

When the rowing team is going against the current, the effective speed is decreased by the speed of the current. So, the rowing speed becomes "r - 2" mph. They traveled a distance of 25 miles at this speed.

Since they took the same amount of time for both distances, we can set up the equation:

Time taken when going with the current = Time taken when going against the current

Distance / Speed = Distance / Speed

50 / (r + 2) = 25 / (r - 2)

To solve this equation, we can cross multiply:

50(r - 2) = 25(r + 2)

50r - 100 = 25r + 50

Simplifying the equation:

25r = 150

Dividing both sides by 25:

r = 6

Therefore, the rate of the rowing team in still water is 6 mph.