√20 - 2√5solve with using adding and subtracting radicals

Neokoenig asked Feb 11, 2023

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Neokoenig asked Feb 11, 2023

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21 votes

the initial expression is:

$\sqrt[]{20}-2\cdot\sqrt[]{5}$

so to rest them we want to have the same radical so we can rewrite the root of 20 so:

$\begin{gathered} \sqrt[]{4\cdot5}-2\cdot\sqrt[]{5} \\ 2\cdot\sqrt[]{5}-2\cdot\sqrt[]{5}=0 \end{gathered}$

Tarleb answered Feb 15, 2023

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