Question

NASA is painting the nose cone of a sounding rocket with a special sealant which reduces the air-drag on the rocket. If they need to do two coats of the sealant, how many square feet are they painting? Use π = 3.14.A. 56.5 ft²B. 27.3 ft²C. 35.3 ft²D. 28.3 ft²

Answer 1

In order to determine the number of required square feet to paint the nose cone, use the following formula for the surface area of a cone without the base:

`S=\pi rl`

where

r: radius of the base of the cone = 3 ft

l: slant height of the cone = 6 ft

replace the previous values of the parameters into the formula for S and simplify:

`S=(3.14)(3ft)(6ft)=56.5ft^2`

Hence, 56,5ft^2 are required