Question

Complete the table of order pairsfor the given linear equationx+4y = 16x | y0 0 1

Answer 1

Given the equation:

`x+4y=16`

to find the first value, we have to make x = 0 and solve for y, then, we have the following:

`\begin{gathered} x=0 \\ \Rightarrow0+4y=16 \\ \Rightarrow4y=16 \\ y=(16)/(4)=4 \\ y=4 \end{gathered}`

then, on the first row, the value of y is 4.

For the next two, notice that we now have values for y, this means that we have y = 0 and y = 1. Solving each case for x, we get:

`\begin{gathered} y=0 \\ \Rightarrow x+4(0)=16 \\ x=16 \end{gathered}`

and

`\begin{gathered} y=1 \\ \Rightarrow x+4(1)=16 \\ \Rightarrow x=16-4=12 \\ x=12 \end{gathered}`

therefore, the table should look like this: