Question

Solve for the area of a parallelogram that has a base of 1/2 in and a height of 8 in.

Answer 1

The area of a parallelogram is given by the equation:

`A=b* h`

Where b is the base of the parallelogram and h is the height.

In this case, b=1/2 in and h=8in, then:

`\begin{gathered} A=((1)/(2)in)(8in) \\ =4in^2 \end{gathered}`

Therefore, the area of the described parallelogram, is:

`4in^2`