Question

Drag the expressions in order from least to greatest value.

Answer 1

`1(7)/(8)=(1\cdot8+7)/(8)=(15)/(8)`
`1(7)/(8)-(1)/(4)=(15)/(8)-(1)/(4)=(15-1\cdot2)/(8)=(13)/(8)`
`1(1)/(8)=(1\cdot8+1)/(8)=(9)/(8)`
`1(1)/(8)+(1)/(4)=(9)/(8)+(1)/(4)=(9+1\cdot2)/(8)=(11)/(8)`
`1(1)/(2)=(1\cdot2+1)/(2)=(3)/(2)`
`1(1)/(2)-(5)/(8)=(3)/(2)-(5)/(8)=(3\cdot4-5)/(8)=(7)/(8)`

Then, from least to greatest value, the order is:

`1(1)/(2)-(5)/(8)`
`1(1)/(8)+(1)/(4)`
`1(7)/(8)-(1)/(4)`