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What is the equation for a line that passes through the points (5.-3) and (-10,15)?
y = -2-3
4

User Mayday
by
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1 Answer

4 votes

Answer:

y = - 6/5 x + 3

Explanation:

Slope (m) = (y-y)/(x-x)

m = (15 - - 3)/(-10 - 5)

m = 18/-15 = - 6/5

y-y = m(x-x)

m = -6/5, point: (5,-3)

y - - 3 = -6/5(x - 5)

y + 3 = -6/5 x + 30/5

y = -6/5x + 6 - 3

y = - 6/5x + 3

User KarSho
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8.0k points