Question

For the following equation, evaluate dy when x = -1.
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y = −3x² + 5
Answer

Answer 1

To find the value of `y` when `x = -1` in the equation `y = -3x² + 5`, we substitute `-1` for `x`:

y = -3(-1)² + 5

y = -3(1) + 5

y = -3 + 5

y = 2

So, when `x = -1`, `y = 2`.

Explanation:

Answer 2

6

Explanation:

To find dy/dx, we use the power rule:

`\sf (d)/(dx)(x^n) = nx^(n-1)`

Applying the power rule to the given equation, we get:

`\sf dy/dx = -3(2x^(2-1)) = -6x`

Now, let's evaluate dy/dx when x = -1:

dy/dx = -6(-1) = 6

Therefore, the dy/dx is -6x, and when x = -1, dy/dx is 6.