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Consider the system of equations, x-2y = 8 and -2x + 4y = -16.

What is x - 2y = 8 in slope-intercept form?
y=(1/2)x-4
What is -2x + 4y = -16 in slope-intercept form?
How many solutions will there be?
What will the graph of the system look like?

1 Answer

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Final answer:

To write the equations in slope-intercept form, x - 2y = 8 can be represented as y = (1/2)x - 4 and -2x + 4y = -16 can be represented as y = (1/2)x - 4. The system has infinitely many solutions, and the graph of the system will be a line.


Step-by-step explanation:

To write the equation x - 2y = 8 in slope-intercept form, y = mx + b, we need to isolate y. So, we can start by moving x to the other side of the equation:

x - 2y + 2y = 8 + 2y

x = 2y + 8

Now, we can solve for y by dividing both sides of the equation by 2:

y = (1/2)x - 4

Therefore, x - 2y = 8 in slope-intercept form is y = (1/2)x - 4.

To write the equation -2x + 4y = -16 in slope-intercept form, we need to isolate y as well. Here's the process:

-2x + 4y = -16

4y = 2x - 16

y = (1/2)x - 4

Therefore, -2x + 4y = -16 in slope-intercept form is y = (1/2)x - 4.

Since both equations have the same slope and y-intercept, they represent the same line. Therefore, the system will have infinitely many solutions, and the graph of the system will be a line.


Learn more about slope-intercept form of equations

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