Final answer:
To find the probability of a temperature of 98.2 degrees F or less, we need to standardize the temperature value and use the z-score formula. The resulting z-score can be used to find the area under the normal distribution curve, which represents the probability. The calculated probability is 0.258.
Step-by-step explanation:
To calculate the probability that a randomly chosen individual would have a temperature of 98.2 degrees F or less, we need to standardize the temperature value using the standard deviation. Standardizing allows us to use the z-score formula to find the corresponding area under the normal distribution curve. First, find the z-score using the formula: z = (x - μ)/σ, where x is the temperature value, μ is the mean, and σ is the standard deviation. In this case, x = 98.2, μ = 98.6, and σ = 0.62. Substituting these values, we get z = (98.2 - 98.6)/0.62 = -0.645. Then, we can use the z-score to find the area under the normal distribution curve using a z-score table or calculator. The area to the left of the z-score of -0.645 is approximately 0.258. Therefore, the probability that a randomly chosen individual would have a temperature of 98.2 degrees F or less is 0.258.
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