Question

Triangle ABC, with vertices A(-2, 4), B(0, -5), and C(-3, -8) was dilated to form triangleA'B'C' with vertices A(-1.8, 3.6), B(0, -4.5), and C(-2.7, -7.2). What rule represents thedilation applied?(x, y) = (2/3x, 2/3y)(x, y) - (0.9x, 0.9y)(x, y) - (-X, -Y)(x, y) - (1.2x, 1.25y)

Answer 1

A = (-2,4)

B= (0,-5)

C = (-3,-8)

A'= (-1.8, 3.6 )

B'= (0, -4.5 )

C' = (-2.7, -7.2)

Try each option:

(x, y) = (2/3x, 2/3y)

A = (-2,4) = (2/3*-2 , 2/3*4) = (-4/3, 8/3) NOt equal to A'

(x, y) - (0.9x, 0.9y) =

A = (-2,4) = (0.9*-2, 0.9*4) = (-1.8, 3.6) = A' YES

B = (0,-5) = (0.9*0, 0.9*-5) = (0, -4.5) = B'

C= (-3,-8) = (0.9*-3, 0.9*-8) = ( -2.7, -7.2)= C'

Correct option : (x, y) - (0.9x, 0.9y)