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(-4, 6); slope = - 3/4write the linear equation in slope intercept form given

User Arek
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1 Answer

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14 votes

We know the slope = -3/4 and a point = (-4, 6) of a line, and we wnat to find the equation in the slope-intercept form, so:


\begin{gathered} \text{The general slope-intercept form of a line is:} \\ y=mx+b \\ \text{Where m is the slope and b is the value of y-intercept} \end{gathered}

In this case, m=-3/4 and evaluating the point (-4, 6) we can find the value of b:


\begin{gathered} \text{With m=-3/4 and the point (x, y) = (-4, 6):} \\ 6=-(3)/(4)(-4)+b \\ 6=3+b \\ b=6-3 \\ b=3 \end{gathered}

We found that b = 3, so the equation of the line is:


y=-(3)/(4)x+3

User Izumi
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