Answer:
The chemical reaction between solid rubidium (Rb) and aqueous zinc nitrate (Zn(NO3)2) can be represented as follows:
Rb(s) + Zn(NO3)2(aq) -> RbNO3(aq) + Zn(s)
Now, let's balance the equation:
Rb(s) + Zn(NO3)2(aq) -> RbNO3(aq) + Zn(s)
The balanced equation is already balanced as it is. There is one rubidium (Rb) atom on both sides, one zinc (Zn) atom on both sides, and two nitrate (NO3) ions on both sides, so it is balanced.