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A line passes through the points (-8, -7) and (-4,-4). What is the equation of the line in Slope-Intercept Form?

Oy=x+1
O y = ³r+1
Oy=-1
0 y=x-1

User Wiseass
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Final answer:

The equation of the line passing through the given points (-8, -7) and (-4, -4) in slope-intercept form is y = (3/4)x - 1.


Step-by-step explanation:

To find the equation of a line in slope-intercept form, we use the formula y = mx + b, where m represents the slope and b represents the y-intercept. We can determine the slope (m) by using the formula: m = (y2 - y1) / (x2 - x1). Given the points (-8, -7) and (-4, -4), we can find the slope: m = (-4 - (-7)) / (-4 - (-8)) = 3 / 4.

Now that we have the slope, we can substitute the values of one of the given points (e.g., (-8, -7)) into the equation to solve for b. Using y = mx + b and substituting the values, we have: -7 = (3/4)(-8) + b. Solving for b, we get b = -1.

Therefore, the equation of the line in slope-intercept form is: y = (3/4)x - 1.


Learn more about Equations of a line in slope-intercept form

User Luigi Ballabio
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