Final answer:
Immiscible liquids do not mix to form a homogeneous solution. Pair A (Br2 + CCl4), Pair C (C6H6 + C8H18), and Pair D (C8H18 + CH3OH) would be immiscible since they have similar intermolecular forces and do not mix with each other.
Step-by-step explanation:
Immiscible liquids are those that do not mix together to form a homogeneous solution.
From the given options:
A. Br2 + CCl4: Bromine (Br2) and carbon tetrachloride (CCl4) are both nonpolar liquids, and they would be immiscible since they have similar intermolecular forces and do not mix with each other.
B. CH3OH + CH3COOH: Methanol (CH3OH) and acetic acid (CH3COOH) are both polar liquids, and they would be miscible since they have similar intermolecular forces and can form hydrogen bonds with each other.
C. C6H6 + C8H18: Benzene (C6H6) and octane (C8H18) are both nonpolar liquids, and they would be immiscible since they have similar intermolecular forces and do not mix with each other.
D. C8H18 + CH3OH: Octane (C8H18) is a nonpolar liquid, while methanol (CH3OH) is a polar liquid. Since they have different intermolecular forces, they would be immiscible with each other.
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