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7. What is the equation in slope-intercept form that passes through the point (-3.5) and is

perpendicular to the line represented by y= 7-47

User Barnardh
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1 Answer

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Final answer:

The equation in slope-intercept form that passes through the point (-3,5) and is perpendicular to the line is y - 5 = (-1/7)(x + 3).


Step-by-step explanation:

The equation in slope-intercept form can be written as y = mx + b, where m represents the slope of the line and b represents the y-intercept.

To find the equation that is perpendicular to the line y = 7x - 47, we need to find the negative reciprocal of the slope of the given line. The given line has a slope of 7, so the perpendicular line will have a slope of -1/7.

Since the line passes through the point (-3, 5), we can substitute the x and y values into the equation to solve for b. Using the point-slope form of the equation, we have the equation: y - y1 = m(x - x1). Substituting the values, we have y - 5 = (-1/7)(x + 3).


Learn more about slope-intercept form of an equation

User Jude Osborn
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