53.4k views
4 votes
Find the p-value when the t-test value is 2.056, the sample size is 11 and the test is right-tailed

User Spydernaz
by
7.7k points

1 Answer

4 votes

Answer:

Answer: p-value = 0.078

The p-value is calculated using the following formula:

p-value = (1 - (1 - t Critical))^((n - 1) / (2 * (t Critical)^2))

where:

* t Critical is the critical value of the t-distribution with (n - 1) degrees of freedom, which is approximately equal to 1.704 for a right-tailed test with 11 observations.

* n is the sample size, which is 11 in this case.

Plugging in the values, we get:

p-value = (1 - (1 - 1.704))^((11 - 1) / (2 * (1.704)^2))

= (1 - 0.847)^(10 / 3.408)

= 0.078

Therefore, the p-value is 0.078, indicating that the observed difference between the sample mean and the population mean is unlikely to be statistically significant at the 0.05 level.

Explanation:

User Davut
by
8.3k points