Answer:
The product of bromination of cyclohexene with pyridinium tribromide is 1,2-dibromocyclohexane.
When cyclohexene reacts with pyridinium tribromide, the double bond in cyclohexene undergoes electrophilic addition with the bromine atoms from pyridinium tribromide. This reaction is known as bromination and results in the addition of two bromine atoms across the double bond.
The mechanism of this reaction involves the formation of a cyclic bromonium ion intermediate. Initially, one of the bromine atoms from pyridinium tribromide attacks the double bond, forming a cyclic bromonium ion. The positive charge on the bromine atom is stabilized by resonance with the adjacent carbon atoms.
Next, a nucleophilic attack occurs by another bromine atom from pyridinium tribromide on the cyclic bromonium ion. This leads to the opening of the cyclic intermediate and formation of a 1,2-dibromocyclohexane product.
The final product, 1,2-dibromocyclohexane, consists of a cyclohexane ring with two bromine atoms attached to adjacent carbon atoms. The bromine atoms are added across the double bond in an anti-addition manner, meaning they are added on opposite sides of the molecule.
In summary, the reaction between cyclohexene and pyridinium tribromide results in the formation of 1,2-dibromocyclohexane through electrophilic addition of two bromine atoms across the double bond.
Step-by-step explanation: