Question

(x+3)^2+(y-4)^2=16please provide the center and the radius

Answer 1

Given:

Given the equation of the circle

`(x+3)^2+(y-4)^2=16`

Required: Radius and center of the circle

Explanation:

The standard form of an equation of a circle is of the form

`(x-h)^2+(y-k)^2=r^2`

where (h, k) is the center and r is the radius.

Re-write the given equation of circle in standard form.

`(x-(-3))^2+(y-4)^2=4^2`

Comparing with the standard form,

center: (h, k) = (-3, 4)

Radius: r = 4

Final Answer: Center = (-3, 4) and radius = 4.