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How many moles of water are in a 39.2 L container at 6.32 atm and 486 °C?

User Babatunde Mustapha
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1 Answer

22 votes
22 votes

Step 1

Water is supposed to be in the gas phase and it is assumed that it is an ideal gas.

Therefore, it can be applied:

p x V = n x R x T (1)

p = pressure = 6.32 atm

V = volume = 39.2 L

n = moles = unknown

R = gas constant = 0.082 atm L/mol K

T = absolute temperature = 486 °C + 273 = 759 K

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Step 2

n is cleared from (1):

p x V/R x T = n

(6.32 atm x 39.2 L)/(0.082 atm L/mol K x 759 K) = n

3.98 moles = n

Answer: number of moles = 3.98 moles

User JohnV
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