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⚠️PLEASEE HELP WITH AN EXPLANATION IM GENUINELY TRYING TO UNDERSTAND THIS QUESTION⚠️

The graph represents the velocity-time graph for a 2.0 kilogram mass moving along a horizontal frictionless surface. What distance does the mass move during interval EF?

⚠️PLEASEE HELP WITH AN EXPLANATION IM GENUINELY TRYING TO UNDERSTAND THIS QUESTION-example-1

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Answer:To find the distance moved during interval EF on the velocity-time graph, we need to calculate the area under the graph within that interval.

First, let's identify the interval EF on the graph. The interval EF represents a constant velocity since the line is horizontal.

The distance moved during a constant velocity interval is equal to the product of the velocity and the time interval.

To find the velocity during interval EF, we need to determine the value of the horizontal line. Let's assume the velocity is v.

Next, we need to determine the time interval. We can use the coordinates of points E and F to find the time difference between them. Let's assume the time interval is t.

Therefore, the distance moved during interval EF can be calculated as:

distance = velocity × time

distance = v × t

The value of v and t can be determined from the graph or given in the question.

Make sure to substitute the correct values for v and t into the formula to find the distance.

To summarize:

- The distance moved during interval EF on the velocity-time graph is given by the formula distance = velocity × time, where velocity (v) is the value of the horizontal line representing the constant velocity and time (t) is the time interval between points E and F.

Explanation:

User Rashidul Islam
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