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Solve the equation for b 4a + 6c – 2b = 12 .​

1 Answer

8 votes

Answer:

b=2a+3c−6

Explanation:

Let's solve for b.

4a+6c−2b=12

Step 1: Add -4a to both sides.

4a−2b+6c+−4a=12+−4a

−2b+6c=−4a+12

Step 2: Add -6c to both sides.

−2b+6c+−6c=−4a+12+−6c

−2b=−4a−6c+12

Step 3: Divide both sides by -2.

−2b

−2

=

−4a−6c+12

−2

b=2a+3c−6

Answer:

b=2a+3c−6

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