Question

A rock is thrown horizontally from the top of a 494.9 m high cliff on Earth near sea level with an initial velocity of 27.6. The ground below the cliff is level. How long, in seconds, will it take the rock to hit the ground below the cliff? Enter your answer at least to the nearest tenth of a second, but do not include units in your answer.​

Answer 1

Time 10.0 s

Step-by-step explanation:

Given:

H = 494.9 m

V = 27.6 m/s

g = 9.8 m/s²

___________

t - ?

The fall time is found from the formula:

H = g·t² / 2

t = √ (2·H / g) = √ (2·494.9 / 9.8 ) ≈ 10.0 s

Attention! An extra given is speed. Find the distance from the base of the rock to the point where the stone fell:

L = V·t = 27.6·10.0 = 276 m