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Find the distance between the points.
a. (-8, -2) and (6, -1)
b. (-4, 5) and (4, 0)​

User Gimelist
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2 Answers

3 votes

To find the distance between two points in a Cartesian plane, you can use the distance formula:

Distance = √[(x2 - x1)² + (y2 - y1)²]

a. For the points (-8, -2) and (6, -1):

x1 = -8

y1 = -2

x2 = 6

y2 = -1

Distance = √[(6 - (-8))² + (-1 - (-2))²]

Distance = √[(6 + 8)² + (-1 + 2)²]

Distance = √[14² + 1²]

Distance = √(196 + 1)

Distance = √197

So, the distance between (-8, -2) and (6, -1) is √197 units.

b. For the points (-4, 5) and (4, 0):

x1 = -4

y1 = 5

x2 = 4

y2 = 0

Distance = √[(4 - (-4))² + (0 - 5)²]

Distance = √[(4 + 4)² + (0 - 5)²]

Distance = √[8² + (-5)²]

Distance = √(64 + 25)

Distance = √89

So, the distance between (-4, 5) and (4, 0) is √89 units.

User Uthistran Selvaraj
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6.7k points
4 votes

Answer:

the distance between the points (-8, -2) and (6, -1) is approximately 14.04 units. the distance between the points (-4, 5) and (4, 0) is approximately 9.43 units.

User Erik Karlstrand
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6.8k points