To solve the equation 5(x^2 - 3x) + 2(4x - 7) = 3(2x + 1)^2 - 5x, follow these steps:
Expand and simplify both sides of the equation.
On the left side, expand the expressions within the parentheses:
5x^2 - 15x + 8x - 14 = 3(4x^2 + 4x + 1) - 5x
Now, simplify further:
5x^2 - 7x - 14 = 12x^2 + 12x + 3 - 5x
Combine like terms on both sides of the equation:
5x^2 - 7x - 14 = 12x^2 + 12x + 3 - 5x
First, subtract the terms on the right side from the left side:
5x^2 - 7x - 14 - 12x^2 - 12x - 3 + 5x = 0
Combine like terms on the left side:
(5x^2 - 12x^2) + (-7x - 12x + 5x) - 14 - 3 = 0
-7x^2 - 14x - 17 = 0
Now, we have a quadratic equation. To solve for x, you can use the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)
In this equation, a = -7, b = -14, and c = -17. Plug these values into the quadratic formula:
x = (-(-14) ± √((-14)² - 4(-7)(-17))) / (2(-7))
x = (14 ± √(196 - 476)) / (-14)
x = (14 ± √(-280)) / (-14)
Since the discriminant (the value inside the square root) is negative, this equation has complex solutions:
x = (14 ± √280i) / (-14)
Simplified:
x = -1 ± √5i
So, the solutions for x are x = -1 + √5i and x = -1 - √5i.