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Find the value of a if the distance between the points (a,7), (2a,-5) equals 13 ​


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Answer:

there are two possible values for "a," which are a = 5 and a = -5, such that the distance between the points (a, 7) and (2a, -5) equals 13.

Explanation:

To find the value of "a" if the distance between the points (a, 7) and (2a, -5) equals 13, you can use the distance formula. The distance formula between two points (x1, y1) and (x2, y2) is given as:

Distance = √((x2 - x1)^2 + (y2 - y1)^2)

In this case, (x1, y1) = (a, 7) and (x2, y2) = (2a, -5). The given distance is 13. So, you have:

13 = √((2a - a)^2 + (-5 - 7)^2)

13 = √(a^2 + (-12)^2)

13 = √(a^2 + 144)

Now, square both sides to isolate a:

169 = a^2 + 144

a^2 = 169 - 144

a^2 = 25

Take the square root of both sides:

a = ±√25

a = ±5

So, there are two possible values for "a," which are a = 5 and a = -5, such that the distance between the points (a, 7) and (2a, -5) equals 13.

User Bilal Akbar
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