Question

At the local supermarket, out of the 100 cartons of eggs on sale, 8 have at least one egg inside that has cracked.

If two cartons are chosen at random from the 100 without replacement, find the probabilities of:
(a) Neither cartons having a cracked egg inside.
(b) Both cartons having at least one cracked cgg inside.
(c) One carton not having a cracked egg inside, while the other having at least one cracked egg inside.

Answer 1

I can not give you the exact answer with this information.

The probability of one carton not having a cracked egg inside while the other has at least one cracked egg inside is:

P(one carton not having a cracked egg inside and the other having at least one cracked egg inside) = [C(92, 1) * C(8, 1) + C(8, 1) * C(92, 1)] / C(100, 2)

The probabilities can be calculated using these formulas.