Final answer:
Approximately 5.858 grams of the 12 gram sample of silver-105 would remain after 57 days.
Step-by-step explanation:
The half-life of silver-105 is approximately 41.3 days. To find out how much of a 12 gram sample of silver-105 would remain after 57 days, we can use the formula:
Amount remaining = Initial amount * (1/2)^(number of half-lives)
First, we need to determine how many half-lives have occurred in 57 days. Since the half-life is 41.3 days, we can divide 57 by 41.3 to get approximately 1.38 half-lives.
Now, we can use the formula to calculate the amount remaining:
Amount remaining = 12 grams * (1/2)^1.38
Calculating this, we find that approximately 5.858 grams of the sample would remain after 57 days.
Learn more about Half-life of silver-105