Answer:
The balanced net ionic equation for the reaction of NaOCl with Na2S2O3 is as follows:
2 NaOCl + Na2S2O3 -> NaCl + Na2SO4 + 2 OCl-
In this reaction, NaOCl and Na2S2O3 react to form NaCl, Na2SO4, and OCl-. OCl- is reduced to chloride ion (Cl-), and S2O3^2- is oxidized into a sulfate ion (SO4^2-).