Question

Which function has a remainder of -70 when divided by (x - 9)?

Select the correct answer below:
O g(x)= x³ - 2x² - 93x + 200
O g(x) = x³ x² - 93x+20
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O g(x) = x³ - 2x² - 90x+200
O g(x)= x³ - 2x²-3x+20
O g(x) = x³ x²-3x+200
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Answer 1

The function that has a remainder of -70 when divided by (x - 9) is g(x) = x³ - 2x² - 93x + 200.

Step-by-step explanation:

To find the function that has a remainder of -70 when divided by (x - 9), we can use the Remainder Theorem. According to the theorem, if a polynomial function f(x) is divided by x - a, the remainder is equal to f(a). Therefore, to get a remainder of -70, we need to find a function that satisfies f(9) = -70.

By evaluating the options, we find that the correct answer is g(x) = x³ - 2x² - 93x + 200. When we substitute x = 9 into this function, we get g(9) = (9)³ - 2(9)² - 93(9) + 200 = -70, which matches the desired remainder.

Learn more about Dividing polynomials