Question

Choose the description(s) of how I could graph the equation y = − 7 x + 1 .  Choose all that apply. Hint: Push the negative either to the top or bottom of the fraction to help you graph.

Answer 1

We are given the following equation in slope-intercept form.

`y=-7x+1`

The general form of slope-intercept form is given by

`y=mx+b`

So, we see that

slope = m = -7

y-intercept = b = 1

The Slope can be written as

`m=\frac{\text{rise}}{\text{run}}=(7)/(-1)=-7`

Also, the y-intercept is the point at which the line crosses the y-axis.

So all those options that say to start on the x-axis are incorrect.

We start at 1 on the y-axis and plot that point.

Then from there, we go up (rise) 7 units and to the left (run) 1 unit.

Go up means positive and go left means negative so the slope becomes -7.

Then plot that point and draw the line connecting the points.

Therefore, there is only one correct answer and that is

Start at 1 on the y-axis. Plot that point. Then from there, go up seven units and left one. Plot that point. Then draw the line connecting the points.

its and left one. Plot that point. Then draw the line connecting the points.

its and left one. Plot that point. Then draw the line connecting the points.

its and left one. Plot that point. Then draw the line connectinits and left one. Plot that point. Then draw the line connectinits and left one. Plot that point. Then draw the line connectinStart at 1 on the y-axis. Plot that point. Then from there, go up seven unG