Question

A line cuts the y-axis at (0, -6) and passes through the point (9, -3). Find the equation of the line.

Answer 1

point 1 (0,-6) and point 2 (9,-3)

the equation is

`y-y1=m(x-x1)`

where m =

`m=(y2-y1)/(x2-x1)=(-3-(-6))/(9-0)=(-3+6)/(9)=(3)/(9)=(1)/(3)`

answer: the equation of the line is

`\begin{gathered} y-(-6)=(1)/(3)(x-0) \\ y+6=(1)/(3)x \\ y+6-6=(1)/(3)x-6 \\ y=(1)/(3)x-6 \end{gathered}`