Question

A ball is thrown into the air from a height of 4 feet at time t=0. The function that models this situation is h(t)=-16t^2+63t+4. What will be the height of the ball after 2 seconds?

Answer 1

66 feet

Explanation:

We know that the t in the equation represents the time. So, substitute 2 for the t in the function and simplify to find the height after 2 seconds:

`h(t) = -16t^2+63t+4\\h(2) = -16(2)^2+63(2)+4\\h(2) = -16(4)+126+4\\h(2) = -64 + 126+4\\h(2) = 66`

Thus, the height would be 66 feet.