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A radioactive substance decays according to the function:

A(t) = A (2.75), where A(t) is the amount of the substance left
after t days, and A, is the initial amount of the substance. If you
start with 4000 units, how many units will be left after 5 days?

1 Answer

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Answer:

To determine the amount of a radioactive substance left after a certain period of time, we can use the decay function A(t) = A(2.75), where A(t) represents the amount of substance remaining after t days, and A is the initial amount of the substance.

In this case, we are given that the initial amount of the substance is 4000 units. Therefore, we can substitute A = 4000 into the decay function to find the amount remaining after a specific time period.

A(t) = 4000 * (2.75)^t

To find the amount remaining after 5 days, we substitute t = 5 into the equation:

A(5) = 4000 * (2.75)^5

Calculating this expression gives us:

A(5) ≈ 4000 * (2.75)^5 ≈ 4000 * 237.3047 ≈ 949,218.8 units

Therefore, approximately 949,218.8 units will be left after 5 days.

Explanation:

User Krishna Agarwal
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