Answer:
there are 40.28 grams of KOH in 125.0 ml of a 5.75 M solution.
Step-by-step explanation:
To calculate the number of grams of KOH (potassium hydroxide) present in a solution, you can use the formula:
Grams of solute = (Molarity) x (Volume in liters) x (Molar mass)
First, convert the volume from milliliters to liters by dividing by 1000:
Volume in liters = 125.0 ml / 1000 = 0.125 liters
The molar mass of KOH is calculated by adding the molar masses of each element:
Molar mass of K (potassium) = 39.10 g/mol
Molar mass of O (oxygen) = 16.00 g/mol
Molar mass of H (hydrogen) = 1.01 g/mol
Molar mass of KOH = 39.10 + 16.00 + 1.01 = 56.11 g/mol
Now, you can use the formula to calculate the grams of KOH:
Grams of KOH = (5.75 M) x (0.125 L) x (56.11 g/mol)
Grams of KOH = 40.28 grams
So, there are 40.28 grams of KOH in 125.0 ml of a 5.75 M solution.
i hope this helps you