Question

Find the perimeter

of the rectangle.
9
13
Use the formula:
p = 21+ 2w
perimeter 2 ×
fength + 2 x width
1 = 13
W = 9
p = [?]

Answer 1

→ 44 units

Explanation:

Given that ,

• Length of rectangle = 13 units

• Width of rectangle = 9 units

We are asked to find ,

• Perimeter of given rectangle

Solution :

We know that ,

`\: \: \: \: \: \: \: \: \: \: \: \boxed{\sf{Perimeter_((Rectangle)) } = 2l + 2w }`

Where ,

• l refers to Length of rectangle

• w refers to Width of rectangle

`\sf{ \: \: \: \: \: \longmapsto \: \: \: \: 2l + 2w}`

`\sf{ \: \: \: \: \: \longmapsto \: \: \: \: 2(13) + 2(9)}`

`\sf{ \: \: \: \: \: \longmapsto \: \: \: \: 26+ 18}`

`\sf{ \: \: \: \: \: \longmapsto \: \: \: \: \underline{ \boxed{\bold{44 \: \: units }}}} \: \: \: \bigstar`

• Therefore, Perimeter of given rectangle is "44 units"

Answer 2

Answer: p = 44

Explanation:

We need to calculate the perimeter of the rectangle, given that:

• l (length) = 13
• w (width) = 9

We'll use the formula:

• p = 2l + 2w

Substitute 13 and 9:

• p = 2(13) + 2(9)
• p = 26 + 18

• p = 44

Therefore, p = 44.