Question

1. A plastic rod is rubbed with a piece of animal fur. The plastic rod acquires a negative charge during this process. Which of the following is true about the charge on the piece of fur? a. charge but greater in It acquires a positive b. It acquires a positive c. charge but less in magnitude than the rod magnitude than the rod 2. Two positive charges with magnitudes 4Q and Q are separated by a distance r. Which of the following statements is true? 4Q Q a. It acquires a positive d. Does not acquire any charge with the same charge magnitude as the rod The charge with a greater b. The charge with a greater c. magnitude exerts a smaller force on the small charge magnitude exerts a larger force on the small charge r The forces on eachd. The forces on each charge are the same in magnitude and opposite in directio charge are the same in magnitude and pointing in the same direction 3. Two positive charges Q₁ and Q2 are separated by a distance r. The charges repel each other with a force F. If the magnitude of each charge is doubled and the distance stays unchanged what is the new force between the charges?​

Answer 1

1) The correct answer is (b) It acquires a positive charge but less in magnitude than the rod.

2) The correct answer is (c) The charge with a greater magnitude exerts a larger force on the small charge Q.

3)If the magnitude of each charge is doubled and the distance remains unchanged, the new force between the charges will be four times the original force.

Step-by-step explanation:

1) Explanation: When a plastic rod is rubbed with animal fur, the rod gains extra electrons and becomes negatively charged. The fur, which loses electrons during the rubbing process, gains a positive charge. However, the magnitude of the charge on the fur is typically less than that on the rod, resulting in a net negative charge on the rod and a net positive charge on the fur.

2 & 3) Explanation: The electric force between two point charges is given by Coulomb's law, which is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. Mathematically, F = k * (Q₁ * Q₂) / r², where F is the force, k is the electrostatic constant, Q₁ and Q₂ are the magnitudes of the charges, and r is the distance between them.When both charges are doubled (2Q₁ and 2Q₂), the new force is given by F' = k * (2Q₁ * 2Q₂) / r² = 4 * (k * Q₁ * Q₂ / r²) = 4F. So, the new force is four times the original force.

Answer 2

c. It acquires a positive charge but less in magnitude than the rod.
c. The charge with a greater magnitude exerts a smaller force on the small charge.
If the magnitude of each charge is doubled and the distance stays unchanged, the new force between the charges will be 8 times the original force. This is because the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them. When both charges are doubled, the product of their magnitudes becomes 4 times greater. Since the distance remains the same, the force increases by a factor of 4. Doubling the charges again results in a total increase of 8 times the original force.