Question

Write an equation in POINT SLOPE FORM of a line through point J(3,-2) with a slope of -5.

Answer 1

y = -5x+13

Explanation:

pt slope form is y = mx + b where m is the slope and b is the y intercept

we are given the slope = -5 so the equation is

y = -5x+b

So to solve for b, plug in that point (3,-2) into the above equation.

y = -5x+b

-2 = -5(3) + b

-2 = -15 + b

-2 + 15 = b

13 = b

y = -5x+13

Answer 2

y + 2 = -5(x - 3)

Explanation:

The point-slope form of a linear equation is:

y - y₁ = m(x - x₁)

where (x₁, y₁) is a point on the line, and m is the slope.

In this case,

We have point J(3, -2) and a slope of -5.

Now

Substitute these values into the point-slope form:

y - (-2) = -5(x - 3)

Simplify the equation:

y + 2 = -5(x - 3)

So, the equation of the line in point-slope form is:

y + 2 = -5(x - 3)