Answer:
Explanation:
The table shows the number of bacteria in each petri dish, with dish C having 8^2 times as many bacteria as dish A. We need to determine which petri dish holds the most number of bacteria.
1. Let's assume that the number of bacteria in dish A is represented by x.
2. According to the information given, dish C has 8^2 times as many bacteria as dish A. This means that the number of bacteria in dish C is (8^2) * x.
3. Simplifying the expression (8^2) * x, we get 64x.
Therefore, dish C has 64 times as many bacteria as dish A.
Based on this, we can conclude that dish C holds the most number of bacteria, as it has a significantly larger number (64 times) compared to dish A.