Question

What is the molality of 1.06 M aqueous solution of sucrose (C12H22O11) which is known to have a specific gravity of 1.14?

Answer 1

0.930 mol/kg

Step-by-step explanation:

Molality = Molarity / Density

The molarity of surcose is 1.06M = 1.06 mol/L

Density of surcose = 1.14 g/mL × 1 kg/1000 g × 1 mL/ 0.001 L = 1.14 kg/L

(1.06 mol/L) / (1.14 kg/L) = 0.930 mol/kg