Answer:
Therefore, after the five-minute period, the temperature of the water would be approximately 41.98°C.
Step-by-step explanation:
To determine the final temperature of the water, we can use the equation:
Q = mcΔT
Where:
Q is the heat lost (in joules)
m is the mass of water (in grams)
c is the specific heat capacity of water (approximately 4.18 J/g°C)
ΔT is the change in temperature (in °C)
In this case, the mass of water is 1000 g, the initial temperature is 50°C, and the heat lost is 33,600 J. We need to find the change in temperature, ΔT.
Rearranging the equation, we have:
ΔT = Q / (mc)
Plugging in the values:
ΔT = 33,600 J / (1000 g * 4.18 J/g°C)
= 8.02°C
Therefore, the change in temperature is 8.02°C.
To find the final temperature, we subtract the change in temperature from the initial temperature:
Final temperature = Initial temperature - ΔT
= 50°C - 8.02°C
= 41.98°C
Therefore, after the five-minute period, the temperature of the water would be approximately 41.98°C.