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A mini-festival lasts a total of 5 hours, with exactly one performer on stage at all times

(including set up and take down), and there are a total of 8 performers. The first 5 performers
average 32 minutes each (including set up and take down) on the stage. What is the average
time that each of the last 3 performers is on stage (including set up and take down)? Answer
in terms of minutes and, if needed, seconds.

1 Answer

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Answer: Here's my first answer ever.

There are an average of 46 minutes and 40 seconds (including set up and take down).

Explanation:

To find the average time that each of the last 3 performers is on stage, we can start by finding the total time the first 5 performers spend on stage.

Since the average time for each of the first 5 performers is 32 minutes, the total time for the first 5 performers can be calculated as 5 performers * 32 minutes per performer = 160 minutes.

Now, let's find the total time the last 3 performers spend on stage. We know that the mini-festival lasts a total of 5 hours, which is equivalent to 5 hours * 60 minutes per hour = 300 minutes.

Since the total time for all the performers is 300 minutes and the total time for the first 5 performers is 160 minutes, we can subtract the time for the first 5 performers from the total time to get the time for the last 3 performers.

Therefore, the total time for the last 3 performers is 300 minutes - 160 minutes = 140 minutes.

To find the average time for each of the last 3 performers, we divide the total time (140 minutes) by the number of performers (3 performers).

Therefore, the average time for each of the last 3 performers is 140 minutes / 3 performers = 46 minutes and 40 seconds.

So, each of the last 3 performers is on stage for an average of 46 minutes and 40 seconds (including set up and take down).

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