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X^2+4x-7=0 by completing the square to 2 dp.
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X^2+4x-7=0 by completing the square to 2 dp.

User Memo
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Answer:

Hi,

Explanation:


x^2+4x-7=0\\x^2+2*2x+2^2-11=0\\(x+2)^2-11=0\\\\(x+2-√(11) )(x+2+√(11) )=0\\\\x=-2+√(11)\ or\ x=-2-sqrt{11} \\\\x\approx{1,32}\ or\ x\approx{-5,32}

User Kanak Singhal
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