Answer:
x<−1 and
�
≥
4
x≥4.
Explanation:
9x−13<−22
−
8
�
+
7
≤
−
25
−8x+7≤−25
Let's solve each of these inequalities separately:
9
�
−
13
<
−
22
9x−13<−22
Add 13 to both sides:
9
�
−
13
+
13
<
−
22
+
13
9x−13+13<−22+13
This simplifies to:
9
�
<
−
9
9x<−9
Now, divide both sides by 9:
9
�
9
<
−
9
9
9
9x
<
9
−9
�
<
−
1
x<−1
So the solution to the first inequality is
�
<
−
1
x<−1.
−
8
�
+
7
≤
−
25
−8x+7≤−25
Subtract 7 from both sides:
−
8
�
+
7
−
7
≤
−
25
−
7
−8x+7−7≤−25−7
Simplify:
−
8
�
≤
−
32
−8x≤−32
Now, divide both sides by -8, and remember to reverse the inequality sign when dividing by a negative number:
−
8
�
−
8
≥
−
32
−
8
−8
−8x
≥
−8
−32
�
≥
4
x≥4
So the solution to the second inequality is
�
≥
4
x≥4.
Therefore, the solutions to the system of inequalities are
�
<
−
1
x<−1 and
�
≥
4
x≥4.