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Objects A and B are dropped from rest near Earth's surface. Object A has mass m and

object B has mass 2m. After 2.0 s of free-fall, object 4 has a speed v and has fallen a
distance d. What are the speed and distance of fall of object B after 2.0 s of free-fall?

User Netro
by
7.7k points

1 Answer

0 votes

When objects are in free fall near Earth's surface, they experience the same acceleration due to gravity regardless of their masses. This acceleration is approximately 9.81 m/s².

For object A:

Mass, m

Time, t = 2.0 s

Acceleration due to gravity, g ≈ 9.81 m/s²

The speed of object A after 2.0 seconds of free fall can be calculated using the equation of motion:

=

v

A

=gt

Substituting the values:

=

(

9.81

/

2

)

(

2.0

)

=

19.62

/

v

A

=(9.81m/s

2

)(2.0s)=19.62m/s

Now, let's find the distance fallen by object A. You can use the following equation of motion:

=

1

2

2

d

A

=

2

1

gt

2

Substituting the values:

=

1

2

(

9.81

/

2

)

(

2.0

)

2

=

19.62

d

A

=

2

1

(9.81m/s

2

)(2.0s)

2

=19.62m

For object B:

Mass, 2m

Time, t = 2.0 s

Acceleration due to gravity, g ≈ 9.81 m/s²

Object B will experience the same acceleration due to gravity, so its speed and distance fallen after 2.0 seconds will be the same as object A:

Speed of object B after 2.0 s:

=

19.62

m/s

v

B

=19.62m/s

Distance fallen by object B after 2.0 s:

=

19.62

m

d

B

=19.62m

So, both object A and object B will have a speed of 19.62 m/s and will have fallen a distance of 19.62 meters after 2.0 seconds of free fall.

User Zachiah
by
7.2k points