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The equation of line c is y–6=–7/6(x–5). Line d, which is parallel to line c, includes the point (5,–7). What is the equation of line d?

User Dplesa
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Answer:

To find the equation of line d, which is parallel to line c and passes through the point (5, -7), we can use the fact that parallel lines have the same slope.

First, let's determine the slope of line c. The equation of line c is given as y - 6 = -7/6(x - 5). We can rewrite this equation in slope-intercept form (y = mx + b), where m represents the slope and b represents the y-intercept.

Starting with the equation of line c:

y - 6 = -7/6(x - 5)

Expanding the brackets:

y - 6 = -7/6x + 35/6

Rearranging to isolate y:

y = -7/6x + 35/6 + 6

y = -7/6x + 35/6 + 36/6

y = -7/6x + 71/6

Comparing this equation to y = mx + b, we can see that the slope (m) of line c is -7/6.

Since line d is parallel to line c, it will have the same slope. Therefore, the equation of line d can be written as:

y = (-7/6)x + b

To find the value of b, we can substitute the coordinates of the given point (5, -7) into this equation and solve for b.

-7 = (-7/6)(5) + b

-7 = -35/6 + b

To simplify this equation, we need to find a common denominator for -35 and 6. The least common multiple of 35 and 6 is 210. Multiplying both sides by 210, we get:

-1470 = -35(210)/6 + 210b

Simplifying further:

-1470 = -35(35) + 210b

-1470 = -1225 + 210b

Adding 1225 to both sides:

-1470 + 1225 = 210b

-245 = 210b

Dividing both sides by 210:

-245/210 = b

-7/6 = b

Therefore, the value of b is -7/6.

Substituting the values of m and b into the equation y = mx + b, we can write the equation of line d as:

y = (-7/6)x - 7/6

So, the equation of line d is y = (-7/6)x - 7/6.

Explanation:

User Abhishek Gurjar
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