Answer:
So, z ≈ 1.42.
Explanation:
To find the value of z such that 0.9282 of the area lies between -z and z, you are essentially looking for the z-score that corresponds to a cumulative probability of 0.9282 in a standard normal distribution (a z-distribution).
You can use a standard normal distribution table or a calculator to find this z-score.
Using a standard normal distribution table or a calculator, you can find that the z-score corresponding to a cumulative probability of 0.9282 is approximately 1.42 (rounded to two decimal places).
So, z ≈ 1.42.